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100x^2-10=71
We move all terms to the left:
100x^2-10-(71)=0
We add all the numbers together, and all the variables
100x^2-81=0
a = 100; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·100·(-81)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*100}=\frac{-180}{200} =-9/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*100}=\frac{180}{200} =9/10 $
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